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10 October, 06:26

An electric field exerts a force of 3.00 E - 4 N on a positive test charge of 7.20 E-4 C. The magnitude of the field at this location of the charge is

a) 0.24 N/C

b) 0.417 N/C

c) 15.6 N/C

d) 21.6 N/C

e) 2.4 N/C

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Answers (1)
  1. 10 October, 06:42
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    3.00 E-4 / 7.20 E-4 = 0.417

    answer is b
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