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20 January, 02:43

An object in space is initially stationary relative to the Earth. Then, a force begins acting on the object, starting with a force of 0 N, and increasing at a uniform rate until the magnitude of the force is 36 N after the force has acted for 35 s. The body has a mass of 10 kg. What is the speed of the object at 35 s?1. 4.4 m/s2. 8.8 m/s3. 11458.3 m/s4. 2750 m/s5. Insufficient information to answer6. 22916.7 m/s7. 110 m/s8. 5500 m/s9. 220 m/s

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  1. 20 January, 02:50
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    v_f = 63 m/s

    Explanation:

    given,

    starting force = 0 N

    uniform rate increase to 36 N

    time of action of Force = 35 s

    mass of the body = 10 Kg

    Speed of the object = ?

    From the given data

    if we plot F-t curve we will get a triangular shape

    we know,

    Impulse = Area between F-t curve

    = (1/2) x base x height

    = 0.5 x 35 x 36

    = 630 N. s

    now use Impulse-momentum theorem

    Impulse = change in momentum

    630 = 10 x (v_f - vi)

    630 = 10 x (v_f - 0)

    v_f = 63 m/s

    Speed of the object at 35 sec is equal to v_f = 63 m/s
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