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22 November, 17:02

A cylinder has 500 cm3 of water. After a mass of 100 grams of sand is poured into the cylinder and all air bubbles are removed by a vacuum pump, the water level rises to 537.5 cm3. Determine the specific gravity of the sand.

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  1. 22 November, 17:09
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    Answer: SG = 2.67

    Specific gravity of the sand is 2.67

    Explanation:

    Specific gravity = density of material/density of water

    Given;

    Mass of sand m = 100g

    Volume of sand = volume of water displaced

    Vs = 537.5cm^3 - 500 cm^3

    Vs = 37.5cm^3

    Density of sand = m/Vs = 100g/37.5 cm^3

    Ds = 2.67g/cm^3

    Density of water Dw = 1.00 g/cm^3

    Therefore, the specific gravity of sand is

    SG = Ds/Dw

    SG = (2.67g/cm^3) / (1.00g/cm^3)

    SG = 2.67

    Specific gravity of the sand is 2.67
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