The resistivity of a silver wire with a radius of 5.04 * 10-4 m is 1.59 * 10-8 ω · m. if the length of the wire is 3.00 m, what is the resistance of the wire?

Question

Lucille Gilmore

Physics

5 January, 09:15

The resistivity of a silver wire with a radius of 5.04 * 10-4 m is 1.59 * 10-8 ω · m. if the length of the wire is 3.00 m, what is the resistance of the wire?

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Alisa · Answer 1

5.98 x 10^-2 ohms. Resistance is defined as: R = rl/A where R = resistance in ohms r = resistivity (given as 1.59x10^-8) l = length of wire. A = Cross sectional area of wire. So plugging into the formula, the known values, including the area of a circle being pi*r^2, gives: R = 1.59x10^-8 * 3.00 / (pi * (5.04 x 10^-4) ^2) R = (4.77 x 10^-8) / (pi * 2.54016 x 10 ^-7) R = (4.77 x 10^-8) / (7.98015 x 10^-7) R = 5.98 x 10^-2 ohms So that wire has a resistance of 5.98 x 10^-2 ohms.