A shot is fired at an angle of 30 degrees with the horizontal from the top of a tower 182.88m. The velocity of projection is 60.90m/s. Find where from the foot of the tower it strikes the ground?

327.41m

Explanation:

The question can be solved using projectile motion equations for Range

R = (U^2 Sin2 thetha) / g

Where U = velocity 60.9m/s

g = acceleration due to gravity 9.81m/s^2

R = (60.9^2 * Sin2*30) / (9.81)

R = (3708.81 * 0.8660) / (9.81)

R = 3211.92/9.81

R = 327.41m