A car traveling at 25 m/s starts to decelerate steadily. It comes to a complete stop in 12 seconds. What is its acceleration?

Question

Roberto Mcfarland

Physics

12 December, 06:44

A car traveling at 25 m/s starts to decelerate steadily. It comes to a complete stop in 12 seconds. What is its acceleration?

+1

Answers (2)

Know the Answer?

Aidan Wong · Answer 1

Acceleration = (change in speed) / (time for the change)

Change in speed = (ending speed) minus (starting speed)

= (0) - (25 m/s) = - 25 m/s

Acceleration = (-25 m/s) / (12 sec) = - 2.083 m/s².

Brayan Hess · Answer 2

Assume it is in uniform deceleration.

u=25

v=0

s=x

a=?

t=12

v=u+at

0=25+a (12)

a=-2.08 (3sig fig)

decelerarion of 2.08 ms^ (-2) /

acceleration=-2.08ms^ (-2)