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19 April, 20:17

A ball of mass 0.16 kg is moving forwards at a speed of 0.50 m/s. A second ball of mass 0.10kg is stationary. The first ball strikes the second ball. The second ball moves forwards at a speed of

0.50 m/s.

What is the speed of the first ball after the collision?

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  1. 19 April, 20:37
    0
    0.19 m/s

    Explanation:

    Momentum before collision = momentum after collision

    m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

    (0.16 kg) (0.50 m/s) + (0.10 kg) (0 m/s) = (0.16 kg) v₁ + (0.10 kg) (0.50 m/s)

    0.08 kg m/s = (0.16 kg) v₁ + 0.05 kg m/s

    0.03 kg m/s = (0.16 kg) v₁

    v₁ ≈ 0.19 m/s
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