A 700-kg car, driving at 29 m/s, hits a brick wall and rebounds with a speed of 4.5 m/s. What is the car's change in momentum due to this collision? A. 2.3x 10^4 kg·m/s towards the wall B. 2.3x 10^4 kg·m/s away from the wall C. 1.7 x 10^4 kg·m/s away from the wall D. 1.7 x 10^4 kg·m/s towards the wall Impulse

Question

Chanel Booth

Physics

5 September, 05:49

A 700-kg car, driving at 29 m/s, hits a brick wall and rebounds with a speed of 4.5 m/s. What is the car's change in momentum due to this collision? A. 2.3x 10^4 kg·m/s towards the wall B. 2.3x 10^4 kg·m/s away from the wall C. 1.7 x 10^4 kg·m/s away from the wall D. 1.7 x 10^4 kg·m/s towards the wall Impulse

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Answers (1)

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Colin Ford · Answer 1

C. 1.7 * 10⁴ kg. m/s away from the wall

Explanation:

Change in momentum: This is the product of mass and change in velocity of a body. The Unit of change in momentum is kg. m/s.

Change in momentum of the car = m (v₂ - v₁) ... Equation 1

Where m = mass of the car, v₁ = initial velocity of the car, v₂ = final velocity of the car.

Given: m = 700 kg, v₁ = 29 m/s, v₂ = 4.5 m/s

Substituting these values into equation 1

Change in momentum of the car = 700 (4.5-29)

Change in momentum of the car = 700 (-24.5)

Change in momentum of the car = 700 (-24.5)

Change in momentum of the car = - 17150 kg. m/s

Therefore the Change in momentum of the car is 1.7 * 10⁴ kg. m/s away from the way wall.

The right option is C. 1.7 * 10⁴ kg. m/s away from the wall