A merry-go-round accelerates from rest to 0.68 rad/s in 34 s. Assuming the merry-go-round to be uniform disk of radius 7.0 m and mass 31,000 kg. The moment of inertia of a uniform disk of mass M and radius R rotating about its axis is MR2/2. Calculate its moment of inertia.

Question

Mckinley Norman

Physics

19 April, 01:47

A merry-go-round accelerates from rest to 0.68 rad/s in 34 s. Assuming the merry-go-round to be uniform disk of radius 7.0 m and mass 31,000 kg. The moment of inertia of a uniform disk of mass M and radius R rotating about its axis is MR2/2. Calculate its moment of inertia.

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Gianna Johnson · Answer 1

759500kgm²

Explanation:

Angular velocity (w) = 0.68rad/s

Time (t) = 34s

Radius (r) = 7m

Mass (m) = 31000kg

Moment of inertia of a circular disk (I) = Mr² / 2

Moment of inertia (I) = (31000 * 7²) / 2

I = 759500kgm²

The moment of inertia of the disk is 759500kgm²