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23 June, 05:14

A rightward force of 302 n is applied to a 28.6 kg crate to accelerate it across the floor. thye coefficient of friction between the crate and the floor is 0.750. determine the acceleration

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  1. 23 June, 05:42
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    We must all look for the fg, fn, Ff, and Fnet to get the acceleration.

    1 Fg = 28.6 (-9.81)

    = 0280.56 n

    2 Fn = 280.56 N

    3 Ff = μFn

    = 0.750 * 280.56

    Ff = 210.425 N

    4. Fnet = Fa + Ff

    = 302 - 210.42

    Fnet = 91.576 N

    5. F = ma

    91.576 = 28.6a

    a = 3.2 m/s
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