The specific angular momentum of a spacecraft in circular Earth orbit is 48,000 km2 / s. Determine the period of the orbit.

T = 5325 s

Explanation:

Given:

- Specific angular momentum h = 48,000 km^2 / s

- Radius of earth r_e = 6.3781 * 10^3 km

Find:

The period of orbit

The relationship between Specific angular momentum h and period of orbit is as follows:

h = 2*pi*r_e^2 / T

T = 2*pi*r_e^2 / h

Hence, Plug the values

T = 2*pi * (6.3781 * 10^3) ^2 / 48,000

T = 5325 s = 1.48 h