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13 December, 01:49

A coin of mass. 005 kg dropped from a height of 3 m. How much potential energy does it have right before it hits the ground? Assume there is no air resistance. Acceleration due to gravity is g=9.8 m/s2

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  1. 13 December, 01:56
    0
    0 J

    Explanation:

    Gravitational potential energy is:

    PE = mgh

    where m is mass, g is acceleration due to gravity, and h is the height.

    Right before the coin hits the ground, its height above the ground is 0 m, so the potential energy is:

    PE = mgh

    PE = (0.005 kg) (9.8 m/s²) (0 m)

    PE = 0 J
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