Ask Question
4 September, 01:05

An 850-lb force is applied to a 0.15-in. diameter nickel wire having a yield strength of 45,000 psi and a tensile strength of 55,000 psi. Determine (a) whether the wire will plastically deform; and (b) whether the wire will experience necking.

+3
Answers (1)
  1. 4 September, 01:29
    0
    a) Yes will deform plastically

    b) Will NOT experience necking

    Explanation:

    Given:

    - Applied Force F = 850 lb

    - Diameter of wire D = 0.15 in

    - Yield Strength Y=45,000 psi

    - Ultimate Tensile strength U = 55,000 psi

    Find:

    a) Whether there will be plastic deformation

    b) Whether there will be necking.

    Solution:

    Assuming a constant Force F, the stress in the wire will be:

    stress = F / Area

    Area = pi*D^2 / 4

    Area = pi*0.15^2 / 4 = 0.0176715 in^2

    stress = 850 / 0.0176715

    stress = 48,100.16 psi

    Yield Strength Ultimate Tensile strength

    45,000 < 48,100 < 55,000

    Hence, stress applied is greater than Yield strength beyond which the wire will deform plasticly but insufficient enough to reach UTS responsible for the necking to initiate. Hence, wire deforms plastically but does not experience necking.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “An 850-lb force is applied to a 0.15-in. diameter nickel wire having a yield strength of 45,000 psi and a tensile strength of 55,000 psi. ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers