A lawn sprinkler sprays water 8 feet at full pressure as it rotates 360 degrees. if the water pressure is reduced by 50%, what is the difference in the area covered?

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Jonas Garrison

Physics

13 October, 05:45

A lawn sprinkler sprays water 8 feet at full pressure as it rotates 360 degrees. if the water pressure is reduced by 50%, what is the difference in the area covered?

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Brooklynn Parsons · Answer 1

The area of the sprinkles can be determined through the area of a circle that is pi * r^2 in which the given dimensions above are the radii, r. The second scenarios radius is only half of the original, that is 4 ft. In this case, we can compute the area of the second again. We calculate next the difference of two areas of circles.