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22 August, 10:58

Two plates separated by a distance d = 14.8 mm are charged to a potential difference V = 7.25 V. A constant force F = 7.81 N pushes a - 8.30 mC charge from the positively charged plate to the negatively charged plate. Calculate the change in the kinetic energy Δ K, potential energy Δ U, and total energy Δ E of the charge as it travels from one plate to the other. Assume the initial speed of the charge is 0.

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  1. 22 August, 11:12
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    change in Kinetic Energy Δ K = 55.388 mJ change in potential energy Δ U = 60.175 mJ total energy ΔE of the charge = 115.563 mJ

    Explanation:

    Part (a) change in Kinetic Energy Δ K

    Δ K = Fd + q (Ed)

    but Ed = V and

    V is given as 7.25 V

    d is given as 14.8 mm

    F is given as 7.81 N

    q is given as - 8.3 mC

    Δ K = Fd + q (V)

    Δ K = (7.81 * 14.8 X 10⁻³) - 8.3 X 10⁻³ * 7.25

    Δ K = 0.055388 J = 55.388 mJ

    Part (b) change in potential energy Δ U

    ΔU = |q|*V

    ΔU = 8.30 X 10⁻³ * 7.25

    ΔU = 60.175 mJ

    Part (c) total energy ΔE of the charge

    ΔE = Δ K + ΔU

    ΔE = 55.388 mJ + 60.175 mJ

    ΔE = 115.563 mJ
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