How many calories of heat must you remove if you want to lower the temperature of 350 g of steel from 18.0 °c to 12.0 °c? the specific heat of steel is 0.11 cal/g °

c.?

Heat to be removed in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:

Heat = mC (T2-T1)

Heat = 350 (0.11) (12.0 - 18.0)

Heat = - 231 cal