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17 September, 13:51

A 90 kg man lying on a surface of negligible friction shoves a 69 g stone away from himself, giving it a speed of 4.0 m/s.

What speed does the man acquire as a result?

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  1. 17 September, 14:15
    0
    v = 3.06 x 10⁻³ m/s

    Explanation:

    given,

    mass of man, M = 90 kg

    mass of stone, m = 69 g = 0.069 Kg

    speed of the stone, u = 4 m/s

    speed of the man, v = ?

    using conservation of momentum

    initial velocity of the man and stone is equal to zero

    (M + m) V = M v + m u

    (M + m) x 0 = 90 x v + 0.069 x 4

    90 v = 0.276

    v = 0.00306 m/s

    v = 3.06 x 10⁻³ m/s

    speed of the man on the frictionless surface is equal to 3.06 x 10⁻³ m/s
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