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18 September, 05:04

Four kilograms of carbon monoxide (co) is contained in a rigid tank with a volume of 1 m3. the tank is fitted with a paddle wheel that transfers energy to the co at a constant rate of 14 w for 1 h. during the process, the specific internal energy of the carbon monoxide increases by 10 kj/kg. if no overall changes in kinetic and potential energy occur, determine (a) the specific volume at the final state, in m3/kg. (b) the energy transfer by work, in kj. (c) the energy transfer by heat transfer, in kj, and the direction of the heat transfer.

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  1. 18 September, 05:33
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    Part (a) : Specific volume

    Specific volume, v = V/m, V = Volume of the tank, m = mass of CO in the tank

    Therefore,

    v = 1/4 = 0.25 m^3/kg

    Part (b) : Energy transferred in kJ

    Work done, W = PΔt, where P = power = 14 W = 14 J/s, t = time = 1 hour = 60*60 = 3600 seconds

    Therefore,

    W = 14*3600 = 50400 J = 50.4 kJ

    Part (c) : Energy transferred by heat

    ΔU = Q + W

    Then,

    Heat transferred by heat, Q = ΔU - W

    But, ΔU = mΔu = 4 kg*10 kJ/kg = 40 kJ

    Therefore,

    Q = 40 - 50.4 = - 10.4 kJ (negative sign indicates that heat is removed from the CO).
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