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3 February, 08:37

A ball is dropped from the top of a cliff 651 m high. How long does it take the ball to hit the ground at the bottom of the cliff, in seconds?

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  1. 3 February, 08:49
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    t = 11.41 seconds

    Explanation:

    h = 1/2 gt^2

    h = height

    g = acceleration due to gravity

    t = time

    651 = 1/2 x 10 x t^2

    651 = 5 x t^2

    t^2 = 651 / 5

    t^2 = 130.2

    t = square root of 130.2

    t = 11.41 seconds
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