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26 January, 19:22

A snowmobile has an initial velocity of 4.7 m/s.

If it accelerates at the rate of 0.73 m/s2 for 5.6s, what is the final velocity? Answer in units of m/s, If instead it accelerates at the rate of - 0.51 m/s2, how long will it take to reach a complete stop? Answer in units of s ... ?

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  1. 26 January, 19:43
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    Q1. The answer is 8.788 m/s

    V2 = V1 + at

    V1 - the initial velocity

    V2 - the final velocity

    a - the acceleration

    t - the time

    We have:

    V1 = 4.7 m/s

    a = 0.73 m/s²

    t = 5.6 s

    V2 = ?

    V2 = 4.7 + 0.73 * 5.6

    V2 = 4.7 + 4.088

    V2 = 8.788 m/s

    Q2. The answer is 9.22 s

    V2 = V1 + at

    V1 - the initial velocity

    V2 - the final velocity

    a - the acceleration

    t - the time

    We have:

    V2 = 0 (because it reaches a complete stop)

    V1 = 4.7 m/s

    a = - 0.51 m/s²

    t = ?

    0 = 4.7 + (-0.51) * t

    0 = 4.7 - 0.51t

    0.51t = 4.7

    t = 4.7 / 0.51

    t = 9.22 s
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