A car travels at a constant speed around a circular track whose radius is 3.27 km. The car goes once around the track in 380 s. What is the magnitude of the centripetal acceleration of the car?

The magnitude of the centripetal acceleration of the car is 0.22 m/s².

Explanation:

t = 380 sec

r = 3.27km = 3270m

d=π*r=π*3270m

d = 10273m

d=Vt*t

Vt = d/t = 10273m/380s

Vt = 27.03 m/s

ac = Vt²/r

ac = (27.03 m/s) ²/3270m

ac=0.22 m/s²