A force F = 73.6 N i + 60.0 N j is applied to a 12.3-kg cart on a level frictionless floor [x-horizontal, y-vertical directions]. The cart starts from rest and moves horizontally along the floor due to this force. What is the cart's instantaneous velocity (m/s) when it is moved by 8.61 m?

Question

Elaina Richard

Physics

27 March, 12:26

A force F = 73.6 N i + 60.0 N j is applied to a 12.3-kg cart on a level frictionless floor [x-horizontal, y-vertical directions]. The cart starts from rest and moves horizontally along the floor due to this force. What is the cart's instantaneous velocity (m/s) when it is moved by 8.61 m?

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Amina · Answer 1

160 Joules

For this problem, we can ignore the vertical component of the applied force and focus on only the horizontal component of 80 N and since work is defined as force over distance, let's multiply the force by the distance: 80 N * 2.0 m = 160 Nm = 160 kg*m^2/s^2 = 160 Joules.

So the cart has a final kinetic energy of 160 Joules.