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2 January, 11:38

A sample of an ideal gas is in a tank of constant volume. The sample absorbs heat energy so that its temperature changes from 235 K to 470K. If v1 is the average speed of the gas molecules before the absorption of heat and v2 their average speed after the absorption of heat, what is the ratio v2 v1

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  1. 2 January, 12:01
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    V2 / V1 = √ (2)

    Explanation:

    From kinetic theory of gas,

    V = √ (3RT/M)

    v = speed of the gas

    R = ideal gas constant

    T = Temperature of the gas

    M = molar mass of the gas

    V = √ (3RT/M)

    V₂ / V₁ = √ (3RT₂/M) / √ (3RT₁/M)

    3R / M = 3R / M = 1

    V₂ / V₁ = √ (T₂ / T₁)

    V₂ / V₁ = √ (470 / 235)

    V₂ / V₁ = √ (2)

    The ratio of the two velocities V₂ / V₁ = √ (2)
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