What is the absolute pressure at a depth of 9.31 m below the surface of a deep lake? take 1.01 * 105 pa as atmospheric pressure?

Question

Jaydin Collier

Physics

4 October, 19:57

What is the absolute pressure at a depth of 9.31 m below the surface of a deep lake? take 1.01 * 105 pa as atmospheric pressure?

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Anton · Answer 1

Stevin's law:

P=dgh+p0

Where p0 is the atmospheric pressure (1.01*10^5 Pa);

d is the liquid density (water, 1000 kg/m³)

g is the gravity acceleration (9.8 m/s²);

h is the depth (9.31m).

P = (1000) (9.8) (9.31) + 101000=192238 Pa