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2 March, 01:09

Estimate the radiation pressure due to a bulb that emits 25 W of EM radiation at a distance of 9.5 cm from the center of the bulb. Assume that light is completely absorbed. Express your answer to two significant figures and include the appropriate units.

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  1. 2 March, 01:18
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    Given Information:

    Power of bulb = w = 25 W atts

    distance = d = 9.5 cm = 0.095 m

    Required Information:

    Radiation Pressure = ?

    Answer:

    Radiation Pressure = 7.34x10⁻⁷ N/m²

    Explanation:

    We know that radiation pressure is given by

    P = I/c

    Where I is the intensity of radiation and is given by

    I = w/4πd²

    Where w is the power of the bulb in watts and d is the distance from the center of the bulb.

    So the radiation pressure becomes

    P = w/c4πd²

    Where c = 3x10⁸ m/s is the speed of light

    P = 25 / (3x10⁸*4*π*0.095²)

    P = 7.34x10⁻⁷ N/m²

    Therefore, the radiation pressure due to a 25 W bulb at a distance of 9.5 cm from the center of the bulb is 7.34x10⁻⁷ N/m²
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