An electron is accelerated uniformly at a rate of 25,000 km/s from rest in an accelerator, over a distance of 125 km. What is the final velocity of the electron?

Answer: 2500km/s

Explanation:

use equation wich conects distance and acceleration:

S=Vst+at²/2

Vs=0km/s (from rest)

S=at²/2

S2=at²

t=√2S/a

t=√2*125km/25000 km/s²

t=0.1s

Vf - -final velocity

Vs- - start velocity

a=Vf-Vs/t

at=Vf-Vs

Vs=0Km/s

at=Vf

25000Km/s*0.1s=Vf

Vf=2500Km/s