Assuming that the smallest measurable wavelength in an experiment is 0.610 fm (femtometers), what is the maximum mass of an object traveling at 199 m·s-1 for which the de Broglie wavelength is observable?.

Question

Jada Charles

Physics

29 May, 08:54

Assuming that the smallest measurable wavelength in an experiment is 0.610 fm (femtometers), what is the maximum mass of an object traveling at 199 m·s-1 for which the de Broglie wavelength is observable?.

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Answers (1)

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Eliza Griffin · Answer 1

1 fm = 1.0 * 10-15 meters

so

0.610 fm x (1.0x10^-15 m / 1 fm)

= 6.1x10^-16 m

so the formula is

λ = h / mu

so,

as we know mass value so by putting

m = (6.626*10^-34) / (6.1*10^-16*199)

= (6.626*10^-34) / (1213.96 * 10^-16)

= 5.45 x 10^ - 21