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20 July, 01:06

An electron in a TV CRT moves with a speed of 6.10 ✕ 107 m/s, in a direction perpendicular to the Earth's field, which has a strength of 5.00 ✕ 10-5 T. (a) What strength electric field (in kV/m) must be applied perpendicular to the Earth's field to make the electron move in a straight line?

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  1. 20 July, 01:23
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    The strength of the electric field is 3.05 kV/m

    Explanation:

    Given;

    speed of electron, v = 6.10 ✕ 10⁷ m/s

    strength of magnetic field, B = 5.00 ✕ 10⁻⁵ T

    Electric force on the electron, F = Eq

    Magnetic force on the electron, F = qvB

    Eq = qvB

    E = vB

    Where;

    E is the electric field strength

    v is the velocity of the electron

    B is the magnetic field strength

    E = vB = 6.10 x 10⁷ x 5.00 x 10⁻⁵

    E = 3050 V/m = 3.05 kV/m

    Therefore, the strength of the electric field is 3.05 kV/m
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