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28 October, 12:37

How long does it take an object thrown in the air with a velocity of 4.5m/s to reach its maximum height

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  1. 28 October, 12:44
    0
    0.46 s

    Explanation:

    At the maximum height, the velocity is 0.

    Given:

    v₀ = 4.5 m/s

    v = 0 m/s

    a = - 9.8 m/s²

    Find: t

    v = at + v₀

    (0 m/s) = (-9.8 m/s²) t + (4.5 m/s)

    t = 0.46 s
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