A car starting at position 16m travels out to position 67m and turns around and speeds back to position 16m. What distance was covered?

A 0m

B 16m

C 67m

D 102m

The answer is D. 102m

Step by step Explanation:

1 - The car starts at position 16m and advances to position 67m, that is, its advance (distance traveled) is equal to position 67m minus position 16m:

67 - 16 = 51

2 - Then the car turns around at position 67m and returns to position 16m (initial position), so it can be concluded that it travels the same distance it did at the beginning (distance traveled since 16m to 57m), so its final advance is equal to:

51 x 2 = 102

So 102 is the distance traveled or covered by the car.

D. 102m?