If the velocity of a car is halved the fc required to keeo it in a path of constant radius is multiplied/divided by?

Question

Asa Gordon

Physics

22 July, 20:25

If the velocity of a car is halved the fc required to keeo it in a path of constant radius is multiplied/divided by?

+3

Answers (2)

Know the Answer?

Skyla Rose · Answer 1

I believe this is it

The centripetal force is given by

F = mv^2 / r

When v' = v/2,

F' = mv'^2/r = m (v/2) ^2/r = mv^2/4r = F/4.

So the centripetal force is divided by 4.

Nathanial West · Answer 2

It should be the 4 ... so the answer is 4 ...