The average density of the body of a fish is 1080kg/m^3. To keep from sinking, the fish increases its volume by inflating an internal air bladder, known as a swim bladder, with air.

By what percent must the fish increase its volume to be neutrally buoyant in fresh water? Use 1.28kg/m^3 for the density of air at 20 degrees Celsius. (change in V/V)

Question

Paola Crawford

Physics

8 November, 21:56

The average density of the body of a fish is 1080kg/m^3. To keep from sinking, the fish increases its volume by inflating an internal air bladder, known as a swim bladder, with air.

By what percent must the fish increase its volume to be neutrally buoyant in fresh water? Use 1.28kg/m^3 for the density of air at 20 degrees Celsius. (change in V/V)

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Answers (1)

Know the Answer?

Pierce Irwin · Answer 1

Increase of volume (F) = 8.01%

Explanation:

Given:

Density of fish = 1,080 kg/m³

Density of water = 1,000 kg/m³

density of air = 1.28 kg/m³

Find:

Increase of volume (F)

Computation:

1,080 kg/m³ + [F * 1.28 kg/m³ ] = (1+F) * 1,000 kg/m³

1,080 + 1.28 F = 1,000 F + 1,000

80 = 998.72 F

F = 0.0801 (Approx)

F = 8.01% (Approx)