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21 July, 22:49

What effect does dropping the sandbag out of the cart at the equilibrium position have on the amplitude of your oscillation? View Available Hint (s) What effect does dropping the sandbag out of the cart at the equilibrium position have on the amplitude of your oscillation? It increases the amplitude. It decreases the amplitude. It has no effect on the amplitude.

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  1. 21 July, 23:14
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    It decreases the amplitude.

    Explanation:

    If it is located at the end, its kinetic energy will be equal to zero, so the system as a whole would only have potential energy, which is defined as:

    Ep = (1/2) * k * A²

    Where A is the amplitude of the oscillation.

    According to the energy principle, said energy must remain conserved, therefore, the total energy is equal to:

    Etot = (1/2) * k * A²

    Since the system is in equilibrium, according to the expression of conservation of energy, the energy in the position located at the end would be equal to the energy in equilibrium. As the sandbag falls, its kinetic energy decreases, which is why the total energy of the system also decreases.

    According to the total energy expression, it is directly proportional to the square of the oscillation amplitude. If the total energy is decreased, the amplitude of the oscillation would also decrease.
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