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31 May, 16:44

A particle of mass 2.0 kg is moving in the xy plane at a constant speed of 0.80 m s in the x direction along the line y 4 m As the particle travels from x 3 m to x 3 m the magnitude of its angular momentum with respect to the origin is?

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  1. 31 May, 17:03
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    6.4 kgm²/s

    Explanation:

    the formula for angular momentum is

    Angular momentum, L = radius/distance, r * linear momentum, p

    i. e L = r * p

    and linear momentum = mass * velocity i. e p = m*v

    Hence, L = m*v*r

    we are given the following:

    mass of particle, m = 2 kg

    velocity/speed of particle, v = 0.8 m/s

    radius/distance, r = the value in y axis = 4m

    substituting the values, we have

    L = 2 * 0.8 * 4 = 6.4 kgm²/s
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