A squirrel runs along an overhead telephone wire that stretches from the top of one pole to the next. It is initially at position x i = 3.47 m, as measured from the center of the wire segment. It then undergoes a displacement of Δx = - 6.29 m. What is the squirrel's final position xf?

Question

Kason Snow

Physics

8 August, 02:04

A squirrel runs along an overhead telephone wire that stretches from the top of one pole to the next. It is initially at position x i = 3.47 m, as measured from the center of the wire segment. It then undergoes a displacement of Δx = - 6.29 m. What is the squirrel's final position xf?

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Answers (1)

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Ronnie Haas · Answer 1

The the squirrel's final position is - 2.82 m

Explanation:

ΔX = Xf - Xi

Where;

ΔX is the displacement in the squirrel's position = - 6.29 m

Xf is the the squirrel's final position = ?

Xi is the the squirrel's initial position = 3.47 m

From the equation above

Xf = ΔX + Xi

Xf = ( - 6.29 + 3.47) m

Xf = - 2.82 m

Therefore, for a squirrel with an initial position of 3.47 m and displacement in position as - 6.29 m, the final position will be - 2.82 m