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19 January, 18:02

D=v^0 t+1/2 at^2 the 0 is supposed to be really small right next to the v under it

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  1. 19 January, 18:26
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    Yes, that's right.

    You mean like this: D = v₀ t + 1/2 a t².

    That's the formula for the distance covered in ' t ' seconds

    by an object that starts out with speed ' v ' and accelerates

    with acceleration of ' a '.

    An example is the vertical distance traveled by a rock that's

    either tossed up from the ground with speed ' v ', or thrown

    down from a roof with speed ' v '.

    Whenever the formula is used for objects thrown up or down,

    the acceleration ' a ' is the acceleration of gravity, on Earth or

    wherever the rock-throwing is going on.
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