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12 June, 12:47

An insulated cup contains 75g of water at 24 degrees. A 26g sample of metal at 82.25 degrees is added. The final temperature of the water and metal is 28.34 degrees. What is the specific heat of the metal?

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  1. 12 June, 13:10
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    Heat lost by the metal = Heat gained the mass of water

    Now,

    Heat = mass*change in temperature*specific heat capacity

    Specific heat of water = 4.18 J/g.°C

    Therefore,

    75*4.18 * (28.34-24) = 26*C * (82.25-28.34) where C = Specific heat of the metal

    C = (75*4.18*4.34) / (26*53.91) = 0.971 J/g.°C
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