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7 September, 07:21

A car is traveling at 33.0 m/s when the driver uses the brakes to slow down to 29.0 m/s in 2.50 seconds. How many meters will it travel during that time?

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  1. 7 September, 07:23
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    Distance traveled during that time is 77.5 m

    Explanation:

    We have equation of motion v = u + at

    Initial velocity, u = 33 m/s

    Final velocity, v = 29 m/s

    Time, t = 2.50 s

    Substituting

    v = u + at

    29 = 33 + a x 2.50

    a = - 1.6 m/s²

    We have equation of motion v² = u² + 2as

    Initial velocity, u = 33 m/s

    Acceleration, a = - 1.6 m/s²

    Final velocity, v = 29 m/s

    Substituting

    v² = u² + 2as

    29² = 33² + 2 x - 1.6 x s

    s = 77.5 m

    Distance traveled during that time is 77.5 m
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