A ball is hit straight up with an initial speed of 28 meters per second. What is the speed of the ball 2.2 seconds after it is hit? [Neglect friction.]

Question

Konnor Stanton

Physics

14 March, 23:52

A ball is hit straight up with an initial speed of 28 meters per second. What is the speed of the ball 2.2 seconds after it is hit? [Neglect friction.]

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Journey · Answer 1

By neglecting friction, the final velocity of the ball thrown upward with an initial speed of v₀ can be calculated through the equation,

vf = v₀ - gt

where vf is final velocity, g is acceleration due to gravity and t is time. Substituting,

vf = 28 m/s - (9.8 m/s²) (2.2. s)

vf = 6.44 m/s

Thus, the final velocity of the ball is approximately 6.44 m/s.