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25 October, 22:15

En un proceso isobárico, la presión del gas es de 105 Pa. Halle el desplazamiento del pistón, cuya área es de 0,4 m2, cuando el gas desarrolla un trabajo de 8 x 104 J

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  1. 25 October, 22:37
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    The displacement of the piston is 1904.76 m

    Explanation:

    Here we have an isobaric or constant pressure process, therefore;

    Work done, W = P * (V₂ - V₁)

    Where:

    W = 8 * 10⁴ J

    P = Pressure of the gas = 105 Pa

    V₁ = Initial volume of the cylinder of the piston

    V₂ = Final volume of the cylinder of the piston

    We note that volume of the cylinder of the piston = Base area, A * h

    Therefore;

    V₁ = A * h₁

    V₂ = A * h₂

    Which gives;

    V₂ - V₁ = A * h₂ - A * h₁ = A * (h₂ - h₁)

    Where:

    A = Base area of the piston = 0.4 m²

    h₂ - h₁ = Displacement of the piston

    ∴ 8 * 10⁴ J = 105 Pa * (V₂ - V₁) = 105 Pa * 0.4 m² * (h₂ - h₁)

    h₂ - h₁ = (8 * 10⁴ J) / (105 Pa * 0.4 m²)

    h₂ - h₁ = 1904.76 m

    Hence the displacement of the piston = 1904.76 m.
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