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7 August, 05:13

A tractor drags a 100 lb. concrete block 5 ft. in 2 seconds. What is the power output of the tractor? 100 ft-lbs. per second 250 ft-lbs. per second 500 ft-lbs. per second 1,000 ft-lbs. per second

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  1. 7 August, 05:28
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    250 [lb-ft/s]

    Explanation:

    To find power we must first find work, which is defined as the product of force by distance.

    W = F*d

    where:

    F = force = 100[lb]

    d = distance = 5 [ft]

    w = 100 * 5 = 500 [lb-ft]

    Now we can calculate the power which is defined as the relationship between work and time.

    P = w / t

    where:

    w = work [lb-ft]

    t = time = 2 [s]

    P = 500 / 2

    P = 250 [lb-ft/s]
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