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17 June, 05:09

A spring is stretched from equilibrium to 0.90 m and the work done on the spring equals 18j what is the value of the spring constant

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  1. 17 June, 05:36
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    Work done is given by 1/2kx^2

    18 = 1/2*k*0.9*0.9

    36 = k*0.81

    44.4 = j/m^2
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