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21 January, 23:52

Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 250 newtons stretches a spring 30 centimeters. How much work is done in stretching the spring from 30 centimeters to 60 centimeters? N-cm

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  1. 22 January, 00:09
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    112.5 J

    Explanation:

    F = 250 N, x = 30 cm = 0.3 m

    Let the spring constant be K.

    By using the Hooke's law

    F = k x

    250 = k x 0.3

    k = 833.3 N / m

    xi = 30 cm = 0.3 m, xf 60 cm = 0.6 m

    Work done = 1/2 k (xf^2 - xi^2)

    Work done = 0.5 x 833.33 x (0.6^2 - 0.3^2)

    Work done = 112.5 J
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