The box moves at a constant speed. If the mass of the box is 4.0 kg, and it is pushed 2.2 m vertically upward, the coefficient of friction is 0.35, and the angle θ is 37°. What is the work done by the force, F? Use g = 10 m/s2.

Question

Sharon Avery

Physics

5 October, 19:47

The box moves at a constant speed. If the mass of the box is 4.0 kg, and it is pushed 2.2 m vertically upward, the coefficient of friction is 0.35, and the angle θ is 37°. What is the work done by the force, F? Use g = 10 m/s2.

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Answers (1)

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Snowy · Answer 1

24.6 J

Explanation:

First, we have to find the force F. Since the force must overcome the frictional force, it will be equal in magnitude to the frictional force.

To find the frictional force:

Fr = - μ * m * g * cosθ

Fr = - 0.35 * 4 * 10 * cos37

Fr = - 11.18 N

The force F will be 11.18N.

Hence, the work done will be:

W = F * d

W = 11.18 * 2.2

W = 24.6 J