Ask Question
26 April, 21:45

How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 4.57*10-21 newtons?

+4
Answers (1)
  1. 26 April, 21:47
    0
    891 excess electrons must be present on each sphere

    Explanation:

    One Charge = q1 = q

    Force = F = 4.57*10^-21 N

    Other charge = q2 = q

    Distance = r = 20 cm = 0.2 m

    permittivity of free space = eo = 8.854*10-12 C^2 / (N. m^2)

    Using Coulomb's law,

    F=[1/4pieo]q1q2/r^2

    F = [1/4pieo]q^2 / r^2

    q^2 = F [4pieo]r^2

    q = r*sq rt F[4pieo]

    q=0.2 * sq rt[ 4.57 x 10^-21]*[4*3.1416*8.854*10^-12]

    q = 1.42614*10^ - 16 C

    number of electrons = n = q/e=1.42614*10^ - 16 / 1.6*10^-19

    n = 891

    891 excess electrons must be present on each sphere
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 4.57*10-21 newtons? ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers