ou slide a slab of dielectric between the plates of a parallel-plate capacitor. As you do this, the charges on the plates remain constant. What effect does adding the dielectric have on the energy stored in the capacitor?

Question

Anton Jordan

Physics

5 January, 03:50

ou slide a slab of dielectric between the plates of a parallel-plate capacitor. As you do this, the charges on the plates remain constant. What effect does adding the dielectric have on the energy stored in the capacitor?

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Hubby · Answer 1

Energy stored in a capacitor is given by the expression

E = Q² / 2C, where Q is charge on it and C is its capacitance. As we put dielectric slab between the plates, capacitance increases, Due to it energy decreases as capacitance form the denominator in the formula above and Q is constant.

Hence energy decreases.