If a projectile is fired with an initial velocity of V meters per second at an angle A above the horizontal and air resistance is assumed to be negligible, then its position after t seconds is given by the parametric equations

x = (Vcos (A)) t,

y = (Vsin (A)) t-12gt2,

A gun is fired with a = 30° and v0 = 500 m/s. When will the bullet hit the ground?

The projectile will hit the ground after about 1min 41 seconds

T=100.7 seconds

Explanation:

The time of flight for a projectile motion is expressed as

T = (2usin0) / g

Where u is the initial velocity

Theta 0 is the projected angle

Assuming g=9.81m/s

Given data

Theta 0 = 30°

u = 500m/s

Substituting our data into the expression we have

T = (2*500*sin30°) / 9.81

T = (1000*-0.988) / 9.81

T=988/9.81

T=100.7 second

The projectile will hit the ground after about 1min 41 seconds