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21 April, 13:11

A 25.0 kg pickle is accelerated from rest through a distance of 6.0m in 4.0s across a level floor. If the friction force betweet the pickle and the floor is 3.8N, what is the work done to move the object

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  1. 21 April, 13:29
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    Add the KE increase and the work done against friction.

    The final velocity is twice the average, or 3.0 m/s

    The final KE is (1/2) * 25*3^2 = 112.5 J

    The friction work done is 6*3.8 = 22.8 J

    hope this is correct
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