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5 May, 18:36

A hammer is accidentally dropped from a scaffold where a crew is working. It takes the hammer 2.5 s to hit the ground. How high is the scaffold?

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  1. 5 May, 18:58
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    30.6 m

    Explanation:

    Given:

    v₀ = 0 m/s

    t = 2.5 s

    a = 9.8 m/s²

    Find: Δy

    Δy = v₀ t + ½ at²

    Δy = (0 m/s) (2.5 s) + ½ (9.8 m/s²) (2.5 s) ²

    Δy ≈ 30.6 m
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