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13 June, 07:07

Chinook salmon are able to move upstream faster by jumping out of the water periodically; this behavior is called porpoising. Suppose a salmon swimming in still water jumps out of the water with a speed of 6.36 m/s at an angle of 45°, sails through the air a distance of L underwater at a speed of 3.58 m/s before beginning another porpoising maneuver. Determine the average speed of the fish.

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  1. 13 June, 07:35
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    Answer:he formula for average speed is (total distance/total time)

    the y-component does not matter in this problem. so do 6.26 (cos45) = 4.43m/s to find the x-component velocity which is constant throughout the duration of the flight. the total distance is 2L because he travels distance L twice.

    the total time is ((time in water) + (time out of water)) since you dont have time you must eliminate it. to do this you need (distance) / (time) = velocity

    solve for time and you get T=D/V

    time in water is L/3.52 and time out of water is L/4.43

    add them together and you get (4.43L+3.52L) / (15.59) = 7.95L/15.59

    that value is your total time

    divide you total distance (2L) by total time (7.95L/15.59) and the Ls cancel out and you get

    (31.18) / (7.95) = 3.92 m/s = Average Speed
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